5x^2+4x+4=32

Solution for 5x^2+4x+4=32 equation:

5x^2+4x+4=32

We move all terms to the left:

5x^2+4x+4-(32)=0

We add all the numbers together, and all the variables

5x^2+4x-28=0

a = 5; b = 4; c = -28;
Δ = b2-4ac
Δ = 42-4·5·(-28)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-24}{2*5}=\frac{-28}{10}
=-2+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+24}{2*5}=\frac{20}{10}
=2
$